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The Times Train Tracks Book 1: 200 challenging visual logic puzzles (The Times Puzzle Books)

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computation time (by a long way) is the final step. This means it's not as wasteful as it might seem at first glance. BEND RAILS TO MAKE THE TRAIN GO ‘CHOO-CHOO’Place, remove and reroute connections so that carriages safely connect to the locomotive. But, be careful and don’t make them run into each other! 240+ PUZZLES TO COMPLETEOur main levels will take you through a variety of locations at a relaxed pace. Forks along the road will lead you to spicy brainteasers that’ll please even the most demanding players! The solver is always the starting point for any type of puzzle - without a solver you won't be able to write a We always start with a solver. We try to make our solver so that it solves puzzles in the same way as a human solver

If there is one unfilled cell left in a row or column at the edge of the unsolved part of the puzzle at some point, it must be adjacent to a filled segment (the rows/columns with the starting and ending points could be the exceptions). We don't like taking this 'brute force' approach to solving any type of puzzle, but sometimes it is the onlyempty cells, and subtract that from the length of that row/column. If this number matches the clue for that a) is there indeed a unique solution, given only the entry and exit points and the row/column totals? (or is there a flaw in my programming/ randomisation?)

The surprise result is that, as far as I can see, there is a unique solution, even without any 'hint' (given) cells being defined. The program will eventually find the same layout again, but it won't (or hasn't yet!) found a different one. Running it for a longer period of time suggests that for approx every 1000 attempts it will find the same layout as the original.These puzzles are not as popular as some other types of puzzles, (Sudoku in particular), but they appear on a daily For example, let's take the puzzle width as 8, and let's suppose the clue for a particular row is 3. the row or column. If the number 1 turns green you have found the right square and the rest can be filled in with x’s. I have been doing these puzzles for a while now and was wondering (a) if there was only one solution to a given puzzle, and (b) if the given cells - there are four in this example and that's usually the case - were actually necessary to solve the puzzle, or just made it easier: and if they were necessary, how many were required? of a puzzle. In this situation somebody solving a puzzle will be able to just 'see' the solution, without

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